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algebra precalculus - Solve the equation $x^4-2x^3-21x^2+22x+40=0$ whose roots are in A.P. - Mathematics Stack Exchange

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Solve the equation $x^4-2x^3-21x^2+22x+40=0$ whose roots are in A.P. (arithmetic progression). I don't understand this solution. Why are the terms of AP considered as mentioned in the question and

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Inter 2nd Year Maths 2A Theory of Equations Important Questions – AP Board Solutions

solve the equation x^4-2x^3-21x^2+22x+40=0 whose roots are in arithmetical progression ​

Inter 2nd Year Maths 2A Theory of Equations Important Questions – AP Board Solutions

Solve the equation [tex]4 {x}^{4} - 28 {x}^{3} + 51 {x}^{2} - 7x - 20 = 0[/tex] whose roots are in

If the roots of x^(4) - 2x^(3) - 21x^(2) + 22x + 40 = 0 are in A.P. then the roots are, 12

If the first 3 terms of an increasing AP are the roots of the cubic 4x3 - 24x2 + 23x - Maths - Sequences and Series - 10618215

given that alpha and beta are the roots of the equation x2=7x+4 Show that alpha3=53alpha+28

Which of the following equations has 2 as a root?a)x2 - 4x + 5 = 0b)x2 + 3x - 12 = 0c)2x2 - 7x + 6 = 0d)3x2 - 6x - 2 =